3x^2-12x+(n-5)=0

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Solution for 3x^2-12x+(n-5)=0 equation:


Simplifying
3x2 + -12x + (n + -5) = 0

Reorder the terms:
3x2 + -12x + (-5 + n) = 0

Remove parenthesis around (-5 + n)
3x2 + -12x + -5 + n = 0

Reorder the terms:
-5 + n + -12x + 3x2 = 0

Solving
-5 + n + -12x + 3x2 = 0

Solving for variable 'n'.

Move all terms containing n to the left, all other terms to the right.

Add '5' to each side of the equation.
-5 + n + -12x + 5 + 3x2 = 0 + 5

Reorder the terms:
-5 + 5 + n + -12x + 3x2 = 0 + 5

Combine like terms: -5 + 5 = 0
0 + n + -12x + 3x2 = 0 + 5
n + -12x + 3x2 = 0 + 5

Combine like terms: 0 + 5 = 5
n + -12x + 3x2 = 5

Add '12x' to each side of the equation.
n + -12x + 12x + 3x2 = 5 + 12x

Combine like terms: -12x + 12x = 0
n + 0 + 3x2 = 5 + 12x
n + 3x2 = 5 + 12x

Add '-3x2' to each side of the equation.
n + 3x2 + -3x2 = 5 + 12x + -3x2

Combine like terms: 3x2 + -3x2 = 0
n + 0 = 5 + 12x + -3x2
n = 5 + 12x + -3x2

Simplifying
n = 5 + 12x + -3x2

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